If a comb rated at 4750 W, 208 V 3 phase draws how many amps?

If a comb rated at 4750 W, 208 V 3 phase draws how many amps?

• A. 10.5
• B. 11.5
• C. 12.2
• D. 13.2

Answer: (D)

To determine the current drawn by a 3-phase load, you can use the formula for calculating current (I) in a 3-phase system, which is: \[ I = \frac{P}{\sqrt{3} \times V} \] Where: - \( P \) is the power in watts (W) - \( V \) is the voltage in volts (V) - \( \sqrt{3} \) is a constant that accounts for the three phases. In this case, the comb is rated at 4750 W and operates at 208 V. Plugging these values into the formula gives: \[ I = \frac{4750}{\sqrt{3} \times 208} \] First, calculate \( \sqrt{3} \) which is approximately 1.732. Now, substitute this value into the equation: \[ I = \frac{4750}{1.732 \times 208} \] Calculating the denominator: \[ 1.732 \times 208 \approx 360.256 \] Now calculate the current: \[ I = \frac{4750}{360.256} \approx 13.2 \, A \] Therefore, the

To determine the current drawn by a 3-phase load, you can use the formula for calculating current (I) in a 3-phase system, which is:

[ I = \frac{P}{\sqrt{3} \times V} ]

Where:

• ( P ) is the power in watts (W)

• ( V ) is the voltage in volts (V)

• ( \sqrt{3} ) is a constant that accounts for the three phases.

In this case, the comb is rated at 4750 W and operates at 208 V. Plugging these values into the formula gives:

[ I = \frac{4750}{\sqrt{3} \times 208} ]

First, calculate ( \sqrt{3} ) which is approximately 1.732. Now, substitute this value into the equation:

[ I = \frac{4750}{1.732 \times 208} ]

Calculating the denominator:

[ 1.732 \times 208 \approx 360.256 ]

Now calculate the current:

[ I = \frac{4750}{360.256} \approx 13.2 , A ]

Therefore, the